Description
如果KM1、KM2所带负载的状态完全相同,只需把KM1、KM2的线圈并联连接,只占用1个输出点Y0,可节省1个输出点;同样图11中,如果Q1、Q2不会同时为接通状态,则可以1个输出点Y1来带动两路不会同时有输出的负载KM3、KM4的输出,从而也节省了一个输出点。
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